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Chapter 5 · Class 10 Mathematics

Arithmetic Progressions — Questions & Answers

Board-pattern questions from Arithmetic Progressions, each with the correct answer and the reasoning behind it. 260 questions from this chapter are on TestSaathi; a few of them are below so you can see what the practice looks like before signing up.

Sample questions from Arithmetic Progressions

  1. Q1. In an AP, if a = 3, n = 8 and Sₙ = 192, then the common difference d is:

    • A.6✓
    • B.8
    • C.4
    • D.12
    Solution

    A is correct. From Sₙ = (n/2)[2a + (n − 1)d], 192 = 4[6 + 7d], so 48 = 6 + 7d, giving 7d = 42 and d = 6. B comes from dividing 192 by 8 and subtracting 3 and then dividing by 7 incorrectly. C halves the correct answer. D comes from using 4d in place of 7d, that is from taking half of n − 1.

  2. Q2. If the first and last terms are a and l, the sum of n terms is:

    • A.n/2(a+l)✓
    • B.n(a+l)
    • C.(a+l)/n
    • D.n/2(a−l)
    Solution

    Sₙ=n/2(a+l).

  3. Q3. Three numbers are in AP. Their sum is 24 and their product is 440. The numbers are:

    • A.4, 8, 12
    • B.6, 8, 10
    • C.3, 8, 13
    • D.5, 8, 11✓
    Solution

    Taking the numbers as a − d, a, a + d gives 3a = 24 so a = 8; then 8(64 − d²) = 440 gives d² = 9, d = 3, i.e. 5, 8, 11.

  4. Q4. The sum of first 15 even natural numbers is: Verify the related AP-sum calculation:

    • A.240✓
    • B.225
    • C.210
    • D.250
    Solution

    2(1+…+15)=15×16=240.

  5. Q5. A machine produces 50 units in the first hour and 5 more each hour. Production in 12 hours is:

    • A.930✓
    • B.900
    • C.960
    • D.870
    Solution

    S₁₂=12/2[100+11×5]=930.

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